Find the equation of a line that has y – intercept – 4 and is parallel to the line joining (2, – 5) and (1, 2).
Given, A line segment joining (2, – 5) and (1, 2) if it cuts off an intercept – 4 from y–axis.
To Find: The equation of that line.
Formula used: The equation of line is y = mx + C
Explanation: Here, The required equation of line is y = mx + c
Now, c = – 4 (Given)
Slope of line joining (x1 – x2) and (y1 – y2) ,
So, Slope of line joining (2, – 5) and (1, 2),
Therefore, m = – 7
Now, The equation of line is y = mx + c
y = –7x – 4
y + 7x + 4 = 0
Hence, The equation of line is y + 7x + 4 = 0.