Find the equation of a line which is perpendicular to the line joining (4, 2) and (3 5) and cuts off an intercept of length 3 on y – axis.
Given, A line segment joining (4, 2) and (3, 5) if it cuts off an intercept 3 from y–axis.
To Find: The equation of that line.
Formula used: The equation of line is y = mx + C
Explanation: Here, The required equation of line is y = mx + c
Now, c = 3 (Given)
Let m be slope of given line = – 1
Slope of line joining (x1 – x2) and (y1 – y2) ,
So, Slope of line joining (4, 2) and (3, 5),
Therefore,
Now, The equation of line is y = mx + c
x – 3y + 9 = 0
Hence, The equation of line is 2y + 5x + 6 = 0.