Given:

Points A (1, 4), B(2, -3) and C(-1, -2).

Assuming:

m_1, m_2, and m₃ be the slope of the sides AB, BC and CA, respectively.

Concept Used:

The slope of the line passing through the two points ( x₁, y₁) and ( x₂, y₂).

The equation of the line passing through the two points ( x₁, y₁) and ( x₂, y₂).

To find:

The equation of sides of the triangle.

Explanation:

m₁, m₂m₃

m_{1 =} -7_, m₂ and m₃ = 3

So, the equation of the sides AB, BC and CA are

Formula used: y – y₁= m (x – x₁)

y – 4 = -7 (x – 1), and y + 2 = 3(x+1)

⇒ 7x + y =11, x+ 3y +7 =0 and 3x – y +1 = 0

Hence, equation of sides are 7x + y =11, x+ 3y +7 =0 and 3x – y +1 = 0