Find the equations to the sides of the triangles the coordinates of whose angular points are respectively:

(0,1), (2, 0) and (-1, - 2)

Given:


Points A (0, 1), B(2, 0) and C(-1, -2).


Assuming:


m1, m2 and m3 be the slope of the sides AB, BC and CA, respectively.


Concept Used:


The slope of the line passing through the two points ( x1, y1) and ( x2, y2).


The equation of the line passing through the two points ( x1, y1) and ( x2, y2).


To find:


The equation of sides of the triangle.


Explanation:


m1m2, m3


m1, m2 and m3= 3


So, the equation of the sides AB, BC and CA are


Formula used: y – y1= m (x – x1)


, and y + 2 = 3(x+1)


⇒ x + 2y = 2, 2x – 3y =4 and 3x – y +1 = 0


Hence, equation of sides are x + 2y = 2, 2x – 3y =4 and 3x – y +1 = 0


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