Find the equation of the side BC of the triangle ABC whose vertices are A (-1, -2), B (0, 1) and C (2, 0) respectively. Also, find the equation of the median through A (-1, - 2).

Given: The vertices of triangle ABC are A (-1, -2), B(0, 1) and C(2, 0).


Concept Used:


The equation of the line passing through the two points ( x1, y1) and ( x2, y2)


To find:


Equation of side BC of triangle ABC.


The equation of median through A.


Explanation:


So, the equation of BC is


Formula used:




x + 2y – 2 = 0


Let D be the midpoint of median AD is


So,


So, the equation of the median AD is


Formula used:



4y + 8 = 5x + 5


5x – 4y – 3 = 0


The equation of line BC is x + 2y – 2 = 0


Hence, the equation of median is 5x – 4y – 3 = 0


5