Given: the vertices of triangle ABC are A (4, 3), B (0, 0) and C (2, 3).

To find:

The equation of bisector of angle A.

Explanation:

Let us find the lengths of sides AB and AC.

AB = 5

AC = = 2

We know that the internal bisector AD of angle BAC divides BC in the ratio AB: AC, i.e. 5: 2

D

Thus, the equation of AD is

Formula used:

⇒

⇒ x – 3y +5 = 0

Hence, the equation of line is x – 3y +5 = 0