Find the equation of a line which passes through the point (22, -6) and is such that the intercept on x-axis exceeds the intercept on the y-axis by 5.
Concept Used:
The equation of the line with intercepts a and b is
Given:
Here, a =b+5 ……..(1)
Explanation:
The line passing through the point (22, -6)
………(2)
Substituting a = b + 5 from equation (1 ) in equation (2)
(b – 5)(b – 6)=0
b = 5, 6
From equation (1)
When b = 5 then a = 10
When b = 6 then a = 11
Thus the equation of the required line is
and
Thus the equations are
x + 2y=10, 6x +11y=66
Hence, the equation of line is x + 2y=10, 6x +11y=66