Find the equation of the line, which passes through P(1, -7) and meets the axes at A and B respectively so that 4AP – 3BP = 0.
Concept Used:
The equation of the line with intercepts a and b is
Assuming:
The line meets the coordinate axes at A and B, So the coordinates A (a, 0) and B (0, b )
Given:
4AP – 3BP = 0
Explanation:
⇒ AP : BP =3 : 4
Here p= (1, -7)
⇒4a = 7,3b = - 49
⇒a = , b =
Thus the equation of the line is
⇒
⇒ 28x – 3y = 49