Find the equations of the straight lines each of which passes through the point (3, 2) and cuts off intercepts a and b respectively on x and y-axes such that a – b = 2.
Concept Used:
The equation of the line with intercepts a and b is
Given:
Here, a – b = 2
⇒ a = b + 2 ……(i)
Explanation:
The line is passing through (3,2).
……(ii)
From equation (i) and (ii)
⇒3b + 2b +4 = b2 + 2b
⇒b2 – 3b – 4 = 0
⇒ (b – 4)(b + 1) = 0⇒b = 4, -1
Now, from equation (i)
For b = 4, a = 4 + 2 = 6
For b = -1, b = -1 + 2 = 1
Thus the equation of line is
or
⇒x – y = 1 or 2x + 3y = 12