Find the equation of a line for which
p = 8, α = 300°
Given: p = 8, α = 300°
Concept Used:
Equation of line in normal form.
Explanation:
So, the equation of the line in normal form is
Formula Used: x cos α + y sin α = p
x cos 300° + y sin 300° = 8
⇒ x cos (360° – 60°) + y sin (360° – 60°) = 8
We know, cos (360° – θ) = cos θ, sin (360° – θ) = – sin θ
⇒ x cos60° – y sin60° = 8
⇒
⇒ x – √3y = 16
Hence, the equation of line in normal form is x – √3y = 16