Find the equation of a line for which

p = 8, α = 300°

Given: p = 8, α = 300°

Concept Used:


Equation of line in normal form.


Explanation:


So, the equation of the line in normal form is


Formula Used: x cos α + y sin α = p


x cos 300° + y sin 300° = 8


x cos (360° – 60°) + y sin (360° – 60°) = 8


We know, cos (360° – θ) = cos θ, sin (360° – θ) = – sin θ


x cos60° – y sin60° = 8



x – √3y = 16


Hence, the equation of line in normal form is x – √3y = 16


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