A line a drawn through A (4, – 1) parallel to the line 3x – 4y + 1 = 0. Find the coordinates of the two points on this line which are at a distance of 5 units from A.
Given: (x1,y1) = A(4, – 1)
To find:
Coordinates of the two points on this line which are at a distance of 5 units from A.
Explanation:
Line 3x – 4y + 1 = 0
⇒ 4y = 3x + 1
⇒ y
Slope
⇒ sin θ and cos θ
So, the equation of the line passing through A (4, −1) and having slope is
Formula Used:
⇒
⇒ 3x – 4y = 16
Here, AP = r = ± 5
Thus, the coordinates of P are given by
⇒
⇒ x and y
⇒ x and y
⇒ x= ±4 + 4 and y = ±3–1
So x = 8, 0 and y = 2, – 4
Hence, the coordinates of the two points at a distance of 5 units from A are (8, 2) and (0, −4).