Find the distance of the line 2x + y = 3 from the point ( – 1, – 3) in the direction of the line whose slope is 1.
Given: (x1,y1) = A( – 1, – 3)
And tan θ = 1 ⇒
To find:
The distance of a point from the line in the direction of the line.
Explanation:
So, the equation of the line passing through ( – 1, – 3) and having slope 1 is
Formula Used:
⇒
⇒ x – y = 2
Let x – y = 2 intersect the line 2x + y = 3 at point P.
Let AP = r
Then, the coordinate of P is given by
⇒ x and y
Thus, the coordinate of P is
Clearly, P lies on the line 2x + y = 3
⇒
⇒ 3r
⇒ r
Hence, the distance of the point ( – 1, – 3) from the line 2x + y = 3 is