Find the coordinates of the vertices of a triangle, the equations of whose sides are :

x + y – 4 = 0, 2x – y + 3 0 and x – 3y + 2 = 0

Given:


x + y − 4 = 0, 2x − y + 3 = 0 and x − 3y + 2 = 0


To find:


Point of intersection of pair of lines.


Concept Used:


Point of intersection of two lines.


Explanation:


x + y − 4 = 0 … (1)


2x − y + 3 = 0 … (2)


x − 3y + 2 = 0 … (3)


Solving (1) and (2) using cross - multiplication method:



x = 1/3, y = 11/3


Solving (1) and (3) using cross - multiplication method:



x = 5/2, y = 3/2


Similarly, solving (2) and (3) using cross - multiplication method:



x = - 7/5, y = 1/5


Hence, the coordinates of the vertices of the triangle are


2