Given:

y = 0 … (1)

x = 2 … (2)

x + 2y = 3 … (3)

Assuming:

In triangle ABC, let equations (1), (2) and (3) represent the sides AB, BC and CA, respectively.

Concept Used:

Point of intersection of two lines.

Explanation:

Solving (1) and (2):

x = 2, y = 0

Thus, AB and BC intersect at B (2, 0).

Solving (1) and (3):

x = 3, y = 0

Thus, AB and CA intersect at A (3, 0).

Similarly, solving (2) and (3):

x = 2, y = 12

Thus, BC and CA intersect at C(2, 12).

∴ Area of triangle ABC =

Hence, area of triangle ABC is .