Find the equation of the line joining the point (3, 5) to the point of intersection of the lines 4x + y – 1 = 0 and 7x – 3y – 35 = 0.

Given:


4x + y − 1 = 0 … (1)


7x − 3y − 35 = 0 … (2)


Concept Used:


Point of intersection of two lines.


Explanation:


Solving (1) and (2) using cross - multiplication method:



x = 2 ,y = - 7


Thus, the point of intersection of the given lines is (2, - 7).


So, the equation of the line joining the points (3, 5) and (2, - 7) is



y - 5 = 12x - 36


12x – y – 31 = 0


Hence, the required equation of line is 12x – y – 31 = 0


7