Given:
2x − 5y + 3 = 0 … (1)

5x − 9y + λ = 0 … (2)

x − 2y + 1 = 0 … (3)

To find:

Value of λ.

Concept Used:

Determinant of equation is zero.

Explanation:

It is given that the three lines are concurrent.

∴

⇒ 2(-9 + 2λ) + 5(5 – λ) + 3(-10 + 9) = 0

⇒ -18 + 4λ + 25 – 5λ – 3 = 0

⇒ λ = 4

Hence, λ = 4.