Find the equation of a line passing through the point (2, 3) and parallel to the line 3x– 4y + 5 = 0.
Given: equation is parallel to 3x − 4y + 5 = 0 and pass through (2, 3)
To find:
Equation of required line.
Explanation:
The equation of the line parallel to 3x − 4y + 5 = 0 is
3x – 4y + λ = 0,
Where, λ is a constant.
It passes through (2, 3).
∴6 – 12 + λ = 0
⇒ λ = 6
Hence, the required line is 3x − 4y + 6 = 0.