Given: equation is perpendicular to and it meets the y-axis.

To find:

The equation of a line drawn perpendicular to the line through the point where it meets the y-axis.

Explanation:

Let us find the intersection of the line with y-axis.

At x = 0,

⇒ y = 6

Thus, the given line intersects y-axis at (0, 6).

The line perpendicular to the line is

This line passes through (0, 6).

⇒ λ

Now, substituting the value of λ, we get:

⇒ 2x -3y + 18 = 0

Hence, the equation of the required line is 2x -3y + 18 = 0