Find the equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2).

Given: A (3, 4) and B ( 1, 2) be the given points


To find:


Equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2).


Explanation:


Let C be the midpoint of AB.


C


Slope of AB


Slope of the perpendicular bisector of AB = -2


Thus, the equation of the perpendicular bisector of AB is


y-3 = -2(x-1)


2x + y – 5 = 0


Hence, the required line is 2x + y – 5 = 0.


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