Find the equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2).
Given: A (3, 4) and B (− 1, 2) be the given points
To find:
Equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2).
Explanation:
Let C be the midpoint of AB.
∴ C
∵ Slope of AB
∴ Slope of the perpendicular bisector of AB = -2
Thus, the equation of the perpendicular bisector of AB is
y-3 = -2(x-1)
⇒ 2x + y – 5 = 0
Hence, the required line is 2x + y – 5 = 0.