Find the equations of straight lines passing through (2, -1) and making an angle of 450 with the line 6x + 5y – 8 = 0.
Given: equation passes through (2,-1) and make an angle of 45° with the line 6x + 5y – 8 = 0
To find: equation of given line
Explanation:
We know that the equations of two lines passing through a point x1,y1 and making an angle α with the given line y = mx + c are
Here,
Equation of the given line is,
6x + 5y – 8 = 0
⇒ 5y = - 6x + 8
Comparing this equation with y = mx + c
we get, m
x1 = 2, y1 = - 1, α = 45°, m
So, the equations of the required lines are
⇒ x + 11y + 9 = 0 and 11x – y – 23 = 0
Hence, Equation of given line is x + 11y + 9 = 0 and 11x – y – 23 = 0