Find the equations of straight lines passing through (2, -1) and making an angle of 450 with the line 6x + 5y – 8 = 0.

Given: equation passes through (2,-1) and make an angle of 45° with the line 6x + 5y – 8 = 0


To find: equation of given line


Explanation:


We know that the equations of two lines passing through a point x1,y1 and making an angle α with the given line y = mx + c are



Here,
Equation of the given line is,


6x + 5y – 8 = 0


5y = - 6x + 8



Comparing this equation with y = mx + c


we get, m


x1 = 2, y1 = - 1, α = 45°, m


So, the equations of the required lines are





x + 11y + 9 = 0 and 11x – y – 23 = 0


Hence, Equation of given line is x + 11y + 9 = 0 and 11x – y – 23 = 0


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