Find the equations of the lines through the point of intersection of the lines x – 3y + 1 = 0 and 2x + 5y – 9 = 0 and whose distance from the origin is.
Given:
Lines x – 3y + 1 = 0 and 2x + 5y – 9 = 0
To find:
The equations of the lines through the point of intersection of the lines x – 3y + 1 = 0 and 2x + 5y – 9 = 0 and whose distance from the origin is.
Explanation:
The equation of the straight line passing through the point of intersection of x − 3y + 1 = 0 and 2x + 5y − 9 = 0 is given below:
x − 3y + 1 + λ(2x + 5y − 9) = 0
⇒ (1 + 2λ)x + (− 3 + 5λ)y + 1 − 9λ = 0 … (1)
The distance of this line from the origin is
⇒ 1 + 81λ2 – 18λ = 145λ2 – 130λ + 50
⇒ 64λ2 – 112λ + 49 = 0
⇒ (8λ – 7)2 = 0
⇒ λ
Substituting the value of λ in (1), we get the equation of the required line.
⇒ 22x + 11y – 55 = 0
⇒ 2x + y – 5 = 0
Hence, equation of required line is 2x + y – 5 = 0.