Given:

Lines 4x + 3y – 11 = 0 and 8x + 6y – 15 = 0

To find:

Distance between lines.

Explanation:

The distance between the two parallel lines ax + by + c₁ = 0 and ax + by + c₂ = 0 is
the given lines can be written as

4x + 3y − 11 = 0 … (1)

8x + 6y – 15 = 0

⇒ … (2)

Let d be the distance between the lines (1) and (2).

Hence,