A line passes through the point (2, 2) and is perpendicular to the line 3x + y = 3. Its y-intercepts is

The equation of the line perpendicular to 3x + y = 3 is given below:


x – 3y + λ = 0


This line passes through (2, 2).


2 – 6 + λ = 0


λ = 4


So, the equation of the line will be


x – 3y + 4 = 0


y = 13x + 43


Hence, the y-intercept is .

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