A(6, 3), B(-3, 5), C(4, -2) and (x, 3x) are four points. If ΔDBC : ΔABC = 1 : 2, then x is equal to

The area of a triangle with vertices D (x, 3x), B ( 3, 5) and C (4, 2) is given below:


Area of DBC


Area of DBC = 14x – 7 sq units


Similarly, the area of a triangle with vertices A (6, 3), B ( 3, 5) and C (4, 2) is given below:




Given:


DBC: ABC = 1: 2



8x – 4 = 7


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