Three vertices of a parallelogram taken in order are (-1, -6), (2, -5) and (7, 2). The fourth vertex is

Let A ( 1, 6), B(2, 5) and C(7, 2) be the given vertex.


Let D(h, k) be the fourth vertex.


The midpoints of AC and BD are and respectively.


We know that the diagonals of a parallelogram bisect each other .



h = 4 and k = 1

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