Let the coordinate of the foot of perpendicular from the point (2, 3) on the line x + y – 11 = 0 be (x, y)

Now, the slope of the perpendicular = -1

The equation of perpendicular is given by

y – 3 = 1(x – 2)

= > x – y + 1 = 0

Solving x + y – 11 = 0 and x – y + 1 = 0, we get

ð x = 5 and y = 6