We need to find the limit for:

As limit can be find out simply by putting x = a because it is not taking indeterminate form(0/0) form, so we will be putting x = a

Let, Z =

⇒ Z =

This can be further simplified using a³ – 1 = (a–1)(a² + a + 1)

⇒ Z =

⇒ Z = (1+a)⁴ + (1+a)² + 1