Prove the following identities:
(sin 3x + sin x) sin x + (cos 3x – cos x) cos x = 0
To prove: (sin 3x + sin x)sin x + (cos 3x – cos x)cos x= 0
Proof:
Take LHS:
(sin 3x + sin x)sin x + (cos 3x – cos x)cos x
= (sin 3x)(sin x) + sin2 x + (cos 3x)(cos x) – cos2 x
= [(sin 3x)(sin x) + (cos 3x)(cos x)] + (sin2 x – cos2 x)
= [(sin 3x)(sin x) + (cos 3x)(cos x)] – (cos2 x – sin2 x)
= cos(3x – x) – cos 2x
{∵ cos 2x = cos2 x – sin2 x &
cos A cos B + sin A sin B = cos(A – B)}
= cos 2x – cos 2x
= 0
= RHS
Hence Proved