A man saves ₹ 32 during the first year, ₹ 36 in the second year and in this way he increases his savings by ₹4 every year. Find in what time his saving will be ₹200.
Given: A man saves Rs. 32 during first year and increases his savings by Rs. 4 every year. His total saving is Rs. 200
To find: Time taken in years by him to save Rs. 200.
A man saves in the first year is 32Rs
He saves in the second year is 36Rs.
In this process he increases his savings by Rs. 4 every year
Therefore,
A.P. will be 32, 36, 40,…………………
where 32 is first term and
common difference, d = 36 – 32 = 4
We know,
Sn is the sum of n terms of an A.P
Formula used:
where a is first term, d is common difference and n is number of terms in an A.P.
According to the question:
Sn = 200
Therefore,
n can not be a negative values as days can not hold negative values
⇒ n = 5
Hence, he has to do saving for 5 days to save Rs. 200