A man saved ₹ 66000 in 20 years. In each succeeding year after the first year he saved ₹ 200 more than what he saved in the previous year. How much did he saved in the first year?
Given: A man saved ₹ 66000 in 20 years
To find: His saving in first year i.e. a
According to question:
n = 20, S20 = 66000 and d = 200
Formula used:
where a is first term, d is common difference and n is number of terms in an A.P.
Therefore,
⇒ 2a = 6600 – 3800
⇒ 2a = 2800
⇒ a = 1400
Hence, his saving in first year is Rs. 1400
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