A bag contains 3 red, 4 white and 5 blue balls. All balls are different. Two balls are drawn at random. The probability that they are of different colour is

As there are 3 +4+5 = 12 balls.


So, 2 balls out of 12 can be drawn in 12C2 ways = 66


Let E denote the event that balls drawn are of different colours


Either the balls will be red-white or white-blue or red-blue.


P(E) =


Hence,


P(E) = 47/66


As our answer matches only with option (a)


Option (a) is the only correct choice.

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