A and B are two events such that P(A) = 0.25 and P(B) = 0.50. The probability of both happening together is 0.14. The probability of both A and B not happening is

Given, P(A) = 0.25 and P(B) = 0.5


Also P(A B) = 0.14


We have to find P(A’ B’)


By De Morgan’s theorem we know that:


P(A’ B’) = P(A B)’


We know that P(A B) = P(A) + P(B) – P(A B)


P(A B) = 0.25 + 0.5 – 0.14 = 0.61


P(A’ B’) = P(A B)’ = 1 -P(A B) = 1 – 0.61 = 0.39


As our answer matches with option (a)


Option (a) is the only correct choice.

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