Three integers are chosen at random from the first 20 integers. The probability that their product is even is

3 integers out of 20 can be chosen in 20C3 ways.


As in first 20 integers, 10 are even.


To have the product of 3 integer even the chosen integers must be even.


3 integers that are even can be chosen from first 20 integers in 10C3 ways.


Probability =


Our answer matches with option (a)


Option (a) is the only correct choice

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