Three integers are chosen at random from the first 20 integers. The probability that their product is even is
3 integers out of 20 can be chosen in 20C3 ways.
As in first 20 integers, 10 are even.
To have the product of 3 integer even the chosen integers must be even.
∴ 3 integers that are even can be chosen from first 20 integers in 10C3 ways.
∴ Probability =
Our answer matches with option (a)
∴ Option (a) is the only correct choice