Total numbers of 4digit that can be formed using 0,2,3,5 without repetition= 3× 3 × 2 × 1 = 18

For number to be divisible by 5 unit digit must end with 5 or 0.

∴ total such numbers(4 digit) ending with zero are = 3× 2× 1(0 is fixed at the unit digit) = 6

∴ total such numbers(4 digit) ending with zero are = 2× 2× 1(5 is fixed at the unit digit) = 4

Total 4 digit numbers using given digit divisible by 5 are 6 + 4 =10

∴ P(a number divisible by 5) = 10/18 = 5/9

As our answer matches only with option (d)

∴ Option (d) is the only correct choice.