Find the equation of the right bisector of the line segment joining the points (3, 4) and ( – 1, 2).
Given, The line segment joining the points (3,4) and ( – 1,2)
To Find: Find the equation of the line
Formula used: The equation of line is (y – y1) = m(x – x1)
Explanation: Here, The right bisector PQ of AB at C and is perpendicular to AB
Now, The coordinate of the mid – points =
The coordinates of point C are = = (1,3)
And, The slope of PQ =
The slope of PQ, m =
SO, The slope of PQ, m = – 2
The required equation of PQ is (y – y1) = m(x – x1)
y – 3 = – 2(x – 1)
y – 3 = – 2x + 2
y + 2x = 5
Hence, The equation of line is y + 2x = 5