Find the equation of the right bisector of the line segment joining the points (3, 4) and ( – 1, 2).

Given, The line segment joining the points (3,4) and ( – 1,2)

To Find: Find the equation of the line


Formula used: The equation of line is (y – y1) = m(x – x1)


Explanation: Here, The right bisector PQ of AB at C and is perpendicular to AB


Now, The coordinate of the mid – points =


The coordinates of point C are = = (1,3)


And, The slope of PQ =


The slope of PQ, m =


SO, The slope of PQ, m = – 2


The required equation of PQ is (y – y1) = m(x – x1)


y – 3 = – 2(x – 1)


y – 3 = – 2x + 2


y + 2x = 5


Hence, The equation of line is y + 2x = 5


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