The mean and standard deviation of 100 observations were calculated as 40 and 5.1 respectively by a student who took by mistake 50 instead of 40 for one observation. What are the correct mean and standard deviation?
To Find: Find the correct mean and standard deviation.
Explanation: Here, n=100,
X =
Now,
Corrected
3990
So, The mean of correct score =
Mean = 39.9
Now, Standard variance = 5.1
Since, Variance =
Variance = 26.01
X =
26.01 =
26.01 =
Corrected -50+40
Corrected
Corrected Variance =
1625.91-1592.01
Corrected variance =34 (Approx)
Now, Corrected Standard Deviation =
Correct Deviation is 5.83
Hence, The correct Mean is 39.9 and Correct SD is 5.83