The mean and standard deviation of 100 observations were calculated as 40 and 5.1 respectively by a student who took by mistake 50 instead of 40 for one observation. What are the correct mean and standard deviation?

To Find: Find the correct mean and standard deviation.


Explanation: Here, n=100,


X =




Now,


Corrected


3990


So, The mean of correct score =



Mean = 39.9


Now, Standard variance = 5.1


Since, Variance =


Variance = 26.01


X =


26.01 =


26.01 =



Corrected -50+40


Corrected


Corrected Variance =



1625.91-1592.01


Corrected variance =34 (Approx)


Now, Corrected Standard Deviation =



Correct Deviation is 5.83


Hence, The correct Mean is 39.9 and Correct SD is 5.83


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