given: die is thrown

Therefore, the total number of outcomes is six

n(S)=6

formula:

(i) let E be the event of getting a prime number

E= {2,3,5}

n(E)=3

(ii) let E be the event of getting 2 or 4

E= {2,4}

n(E)=2

(iii) let E be the event of getting a multiple of 2 or 3

E= {2,3,4,6}

n(E)=4