In a single throw of three dice, find the probability of getting a total of 17 or 18

given: three dices are thrown

formula:


Total number of possible outcomes are 63=216


Therefore n(S)=216


Let E be the event of getting total of 17 or 18


E= {(6,6,5) (6,5,6) (5,6,6) (6,6,6)}


n(E)=4




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