In a single throw of three dice, find the probability of getting a total of 17 or 18
given: three dices are thrown
formula:
Total number of possible outcomes are 63=216
Therefore n(S)=216
Let E be the event of getting total of 17 or 18
E= {(6,6,5) (6,5,6) (5,6,6) (6,6,6)}
n(E)=4