A and B throw a pair of dice. If A throws 9, find B’s chance of throwing a higher number

given: pair of dice

formula:


A and B throw a pair of dice


we have to find the probability that B throw’s a higher number


total possible outcomes are 6C16C1


therefore n(S)= 62=36


let E be the event that A throws 9, and B throws greater than 9


E= {(4,6) (5,5) (5,6) (6,4) (6,5) (6,6)}


n(E)= 6


probability of occurrence of the event is




43