Given two mutually exclusive events A and B such that P(A) = 1/2 and P(B) = 1/3, find P(A or B).

Question

Philoid · Accepted Answer

Given A and B are two mutually exclusive events

And, P(A) = 1/2 P(B) = 1/3

We need to find P(A ‘or’ B).

P(A or B) = P(A ∪ B)

By definition of mutually exclusive events we know that:

P(A ∪ B) = P(A) + P(B)

∴ P(A ∪ B) = P(A) + P(B)

= 1/2 + 1/3 = 5/6