If A and B are mutually exclusive events such that P(A) = 0.35 and P(B) = 0.45, find
(i) P (A ∪ B) (ii) P (A ∩ B)
(iii) (iv)
Given A and B are two mutually exclusive events
And, P(A) = 0.35 P(B) = 0.45
By definition of mutually exclusive events we know that:
P(A ∪ B) = P(A) + P(B)
We have to find-
i) P(A ∪ B) = P(A) + P(B) = 0.35 + 0.45 = 0.8
ii) P(A ∩ B) = 0 {∵ nothing is common between A and B}
iii) P(A ∩ B’) = This indicates only the part which is common with A and not B ⇒ This indicates only A.
P(only A) = P(A) – P(A ∩ B)
As A and B are mutually exclusive So they don’t have any common parts ⇒ P(A ∩ B) = 0
∴ P(A ∩ B’) = P(A) = 0.35
iv) P(A’ ∩ B’) = P(A ∪ B)’ {using De Morgan’s Law}
⇒ P(A’ ∩ B’) = 1 – P(A ∪ B) = 1 – 0.8 = 0.2