Let A = [–1, 1]. Then, discuss whether the following functions defined on A are one-one, onto or bijective:

k(x) = x2

(iv) Given that, A = [–1, 1]


let k(x1) = k(x2)


x12= x22


x1= ± x2


x1= x2 and x1= - x2


For e.g., k(-1) = |-1| = 1 and k(1) = |1| = 1


k is not one-one.


We observe that -1 does not have any pre-image in the domain since k(x) = x2 assumes only non-negative values.


i.e. we cannot find any number in domain which will give -1 in co-domain.


k is not onto


Hence, k is neither one one nor onto.


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