Each of the following defines a relation on N:
x + 4y = 10 x, y ∈N.
Determine which of the above relations are reflexive, symmetric and transitive.
Let R = {(x,y): x + 4y =10, ∀ x,y ∈ N } be a relation defined on N.
R = {(2,2),(6,1)}
Now,
R is not reflexive ∵ (1,1) ∉ R.
R is not symmetric ∵ (6,1) ∈ R but (1,5) ∉ R
R is not transitive
∵ (x,y) ∈ R ⇒ x+4y=10 and (y,z) ∈ R ⇒ y+4z=10
⇒ x-16z = -30
⇒ (x,z) ∉ R
Thus, R is neither symmetric nor reflexive nor transitive.