Construct a 3 × 2 matrix whose elements are given by aij = eixsin jx

A matrix, as we know, is a rectangular array of numbers, symbols, or expressions, arranged in rows and columns.

Also,


We know that, the notation A = [aij]m×m indicates that A is a matrix of order m × n, also 1 ≤ i ≤ m, 1 ≤ j ≤ n; i, j N.


We need to construct a 3 × 2 matrix whose elements are given by


aij = ei.x sin jx


For a3×2:


1 ≤ i ≤ m


1 ≤ i ≤ 3 [ m = 3]


1 ≤ j ≤ n


1 ≤ j ≤ 2 [ n = 2]


Put i = 1 and j = 1.


a11 = e(1)x sin (1)x


a11 = ex sin x


Put i = 1 and j = 2.


a12 = e(1)x sin (2)x


a12 = ex sin 2x


Put i = 2 and j = 1.


a21 = e(2)x sin (1)x


a21 = e2xsin x


Put i = 2 and j = 2.


a22 = e(2)x sin (2)x


a22 = e2x sin 2x


For i = 3 and j = 1.


a31 = e(3)x sin (1)x


a31 = e3x sin x


For i = 3 and j = 2.


a32 = e(3)x sin (2)x


a32 = e3x sin 2x


Let the matrix formed be A.



Substituting the values of a11, a12, a21, a22, a31 and a32, we get the matrix



Thus, we have got the matrix.

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