Construct a 3 × 2 matrix whose elements are given by aij = eixsin jx
A matrix, as we know, is a rectangular array of numbers, symbols, or expressions, arranged in rows and columns.
Also,
We know that, the notation A = [aij]m×m indicates that A is a matrix of order m × n, also 1 ≤ i ≤ m, 1 ≤ j ≤ n; i, j ∈ N.
We need to construct a 3 × 2 matrix whose elements are given by
aij = ei.x sin jx
For a3×2:
1 ≤ i ≤ m
⇒ 1 ≤ i ≤ 3 [∵ m = 3]
1 ≤ j ≤ n
⇒ 1 ≤ j ≤ 2 [∵ n = 2]
Put i = 1 and j = 1.
a11 = e(1)x sin (1)x
⇒ a11 = ex sin x
Put i = 1 and j = 2.
a12 = e(1)x sin (2)x
⇒ a12 = ex sin 2x
Put i = 2 and j = 1.
a21 = e(2)x sin (1)x
⇒ a21 = e2xsin x
Put i = 2 and j = 2.
a22 = e(2)x sin (2)x
⇒ a22 = e2x sin 2x
For i = 3 and j = 1.
a31 = e(3)x sin (1)x
⇒ a31 = e3x sin x
For i = 3 and j = 2.
a32 = e(3)x sin (2)x
⇒ a32 = e3x sin 2x
Let the matrix formed be A.
Substituting the values of a11, a12, a21, a22, a31 and a32, we get the matrix
Thus, we have got the matrix.