Let and a = 4, b = –2.
Show that:
(A – B)C = AC – BC
c) To prove: (A – B)C = AC – BC
As, LHS = (A – B)C
Putting the values of A,B and C and multiplying by rule of matrix multiplication.
LHS =
⇒ LHS =
RHS = AC – BC =
⇒ RHS =
Clearly, LHS = RHS =
Hence (A-B)C = AC - BC…proved