Let and a = 4, b = –2.

Show that:


(A – B)C = AC – BC

c) To prove: (A – B)C = AC – BC


As, LHS = (A – B)C


Putting the values of A,B and C and multiplying by rule of matrix multiplication.


LHS =


LHS =


RHS = AC – BC =


RHS =


Clearly, LHS = RHS =


Hence (A-B)C = AC - BC…proved


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