If possible, using elementary row transformations, find the inverse of the following matrices

Let A =


To apply elementary row transformations we write:


A = IA where I is the identity matrix


We proceed with operations in such a way that LHS becomes I and the transformations in I give us a new matrix such that


I = XA


And this X is called inverse of A = A-1


Note: Never apply row and column transformations simultaneously over a matrix.


So we have:



Applying R2 R2 + R3



Applying R1 R1 - 2R3



Applying R2 R1 + R2



As second row of LHS contains all zeros, So by anyhow we are never going to get Identity matrix in LHS.


Inverse of A does not exist.


A-1 does not exist. …ans


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