If A and B are matrices of same order, then (AB’ – BA’) is a

Let C = (AB’ – BA’)


C’ = (AB’ – BA’)’


C’ = (AB’)’ – (BA’)’


C’ = (B’)’A’ – (A’)’B’


C’ = BA’ – AB’


C’ = -C


C is a skew-symmetric matrix.


Clearly Option (A) matches with our deduction.


Option (A) is the correct.

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