Refer to Exercise 32, Maximum of F – Minimum of F =

F = 4x + 6y


Corner points - (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5).


Value of F at corner points –


At (0, 2), F = 12


At (3, 0), F = 12


At (6, 0), F = 24


At (6, 8), F = 72


At (0, 5), F = 30


Feasible region –



Considering, feasible region to be bounded so it is a closed polygon.


Minimum value of F = 12


Maximum value of F = 72


So, Maximum of F – Minimum of F = 60.

33