The set of points where the function f given by f(x) = |2x – 1| sinx differentiable is
We have, f(x) = |2x – 1| sinx
Now, 2x-1 = 0
⇒ ![]()
Now we will check the differentiability of f(x) at 1/2.

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(∵ f(x) = |2x – 1| sinx)
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(∵ f(x) = |2x – 1| sinx)
=![]()
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=![]()
∴ ![]()
Hence, f(x) is not differentiable at ![]()