A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is

Question

Philoid · Accepted Answer

There are total 8 balls in box.

P(G) , Probability of green ball

P(B) , Probability of blue ball

_{Now, The probability of drawing 2 green balls and one blue ball is}

_{P(E)=P(G).P(G).P(B)+P(B).P(G).P(G)+P(G).P(B).P(G)}

Hence,